CROSSING LADDER PROBLEM

YOU MAY KNOW THE CROSSING LADDER PROBLEM ,BUT THIS BRAIN TEASER IS NOT LIKE THAT .

  
 The problem

Here is a room with two inclined parallel walls.And two ladders are kept inside the room as seen in the picture.The distance between top of the two ladder is 5 ,and distance between the crossing and top of the left ladder is 4.And the question is ,what is the distance from floor to crossing ?




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6 comments:

  1. Solution:
    Since we know the inclined walls are parallel, we know the angles of the cross are the same. So we also know that the sides and height of the triangles are proportional to each other. We can call the scale m. We also know that the height from the top of the highest ladder to the cross section is 9 but we are trying to find x(the question mark). So from what we know we can set up the following equations:

    4m = x
    mx = 9
    4m + mx = x + 9
    4 + x + 5 = x + 9

    => m(4 + x) = (4 + x) + 5
    => (m - 1)(4 + x) = 5
    => (m - 1)(4 + 4m) = 5
    => 4m - 4 + 4m^2 - 4m = 5
    => 4m^2 = 9
    => m^2 = 9/4
    => m = 3/2

    Therefore x = 4(3/2) = 6
    So the height of the question mark is 6.

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  2. I agree with jyim. the left and right triangles are similar, so 9/x = x/4, so x*x = 36, x = 6.

    ReplyDelete
  3. Correct Answer is 6
    Reason:
    Upper Left Triangle ~ Lower Right Triangle
    Lower Left Triangle ~ Upper Right Triangle
    Intercepts on any transversal between 3 parallel lines always bear a constant ratio.So,
    9/x = x/4 implying x = 6

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